[jQuery] Re: take 3 values at time for fade in fade out effect.

What about index_news = index_news + 3 ?

hth

Rick

-----Original Message-----
From: jquery-en@googlegroups.com [mailto:jquery-en@googlegroups.com] On
Behalf Of deep
Sent: Monday, October 26, 2009 9:40 AM
To: jQuery (English)
Subject: [jQuery] Re: take 3 values at time for fade in fade out effect.

I have tried something like this

index_news +=3;

but its not working.

can anyone please help me how can i increase my index_new value by 3?

On Oct 26, 5:07 pm, deep <deeps...@gmail.com> wrote:
> Hello
>
> I have following code which i am using for fade in fade out effect.
> with this code at time only one image is coming. I want at time it
> should show 3 images. like 1,2,3 then 4,5,6
>
> Here is my code.
>
>  var index_news = 0;
>
>    //
>
>    function initNews() {
>
>        $('div#feed-ticker')
>
>        .slideDown('slow',
>
>            function() {
>
>                $('div#feed-ticker li').eq( index_news ).fadeIn();
>
>                setTimeout( next_news, 5000 );
>
>            }
>
>        );
>
>       }
>
>   function next_news() {
>
>       $('div#feed-ticker li')
>
>       .eq( index_news )
>
>       .fadeOut(1000,
>
>           function() {
>
>               index_news++;
>
>               if( index_news> $('div#feed-ticker li').length-1 )
> index_news = 0;
>
>               $('div#feed-ticker li').eq( index_news ).fadeIn();
>
>               setTimeout( next_news, 5000 );
>
>           }
>
>       );
>
>   }
>
> Can anyone tell me how can i set the value here. May be because of
> this  index_news++; its taking one value at time. but how can i
> increase it by 3?
>
> Thanks in advance.