[jQuery] Re: take 3 values at time for fade in fade out effect.
Thanks for your reply Rick
i was trying something similar
index_news =0;
index_news =+3;
but that value is belong to li. so its taking 3 values but showing me
one by one. do i need to write definition for ul then. i am new to
jquery could you please tell me how can i write that?
On Oct 26, 6:48 pm, "Rick Faircloth" <R...@WhiteStoneMedia.com> wrote:
> What about index_news = index_news + 3 ?
>
> hth
>
> Rick
>
> -----Original Message-----
> From: jquery-en@googlegroups.com [mailto:jquery-en@googlegroups.com] On
>
> Behalf Of deep
> Sent: Monday, October 26, 2009 9:40 AM
> To: jQuery (English)
> Subject: [jQuery] Re: take 3 values at time for fade in fade out effect.
>
> I have tried something like this
>
> index_news +=3;
>
> but its not working.
>
> can anyone please help me how can i increase my index_new value by 3?
>
> On Oct 26, 5:07 pm, deep <deeps...@gmail.com> wrote:
> > Hello
>
> > I have following code which i am using for fade in fade out effect.
> > with this code at time only one image is coming. I want at time it
> > should show 3 images. like 1,2,3 then 4,5,6
>
> > Here is my code.
>
> > var index_news = 0;
>
> > //
>
> > function initNews() {
>
> > $('div#feed-ticker')
>
> > .slideDown('slow',
>
> > function() {
>
> > $('div#feed-ticker li').eq( index_news ).fadeIn();
>
> > setTimeout( next_news, 5000 );
>
> > }
>
> > );
>
> > }
>
> > function next_news() {
>
> > $('div#feed-ticker li')
>
> > .eq( index_news )
>
> > .fadeOut(1000,
>
> > function() {
>
> > index_news++;
>
> > if( index_news> $('div#feed-ticker li').length-1 )
> > index_news = 0;
>
> > $('div#feed-ticker li').eq( index_news ).fadeIn();
>
> > setTimeout( next_news, 5000 );
>
> > }
>
> > );
>
> > }
>
> > Can anyone tell me how can i set the value here. May be because of
> > this index_news++; its taking one value at time. but how can i
> > increase it by 3?
>
> > Thanks in advance.
>
>
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