Re: [jQuery] Re: Generate and submit file upload form with jQuery

You could use divs instead of a table. Or use a TD with
colspan=whatever and place another table inside of that (wrap the
table with the form tag).

On Sat, Dec 19, 2009 at 11:15 AM, oli <janoliver@gmail.com> wrote:
> .append($(":input",form).clone())
>
> This line does add all the input fields inside the "form" element
> (which actually isn't a <form>) to the generated one.
>
> The thing is, that I have a table and need a <form> for every row (but
> not in a single column). <form><tr> or <tr><form> aren't valid.
> So I'm looking for all input fields inside the <tr> and generate a new
> one...
>
> On Dec 19, 5:09 pm, brian <zijn.digi...@gmail.com> wrote:
>> Why don't you simply submit the form you are cloning from? It doesn't
>> appear to me that you're adding anything to the new form.
>>
>>
>>
>> On Sat, Dec 19, 2009 at 10:57 AM, oli <janoli...@gmail.com> wrote:
>> > Hi,
>>
>> > I want to collect some input fields that are already present in my
>> > DOM, generate a form with jQuery and submit it. Everything works fine,
>> > unless if one of those input fields is a type="file" field.
>>
>> > $(".trform .sendform").click(function(e) {
>> >    e.preventDefault();
>> >    var form = $(this).closest(".trform");
>>
>> >    var method = form.find(":input[name=method]").val();
>> >    var action = form.find(":input[name=action]").val();
>> >    var enctype = form.find(":input[name=enctype]").val();
>>
>> >    $(document.createElement('form'))
>> >           .attr("method",method)
>> >           .attr("action",action)
>> >           .attr("enctype",enctype);
>> >           .append($(":input",form).clone())
>> >           .submit();
>> > });
>>
>> > If there is a file upload field, it's value after the submit is empty.
>>
>> > Any suggestions what I could do?
>>
>> > Regards, Jan Oliver
>