Re: How to resubmit RPC after session timeout/login

On Feb 5, 10:24 pm, Jamie <jsgreenb...@gmail.com> wrote:
> Hi everybody.  I'm trying to extend AsyncCallback to always have the
> same behavior onFailure.  I can successfully catch the session timeout
> exception that I'm looking for, open a login dialog, and have the user
> login.  What I want to do after that is done is to resubmit the
> original RPC call that caused the onfailure.  Here's what I have so
> far:
>
> <code>
> public abstract class MyAsyncCallback<T> implements AsyncCallback<T> {
>
>         public final void onFailure(Throwable caught) {
>                 if(caught instanceof StatusCodeException &&
> ((StatusCodeException)caught).getStatusCode() == 401) {
>                         final LoginDialog login = new LoginDialog();
>                         login.addLoginDialogListener(new LoginDialogListener() {
>                                 public void loginSuccess() {
>                                         login.hide();
>                                         //RESUBMIT THE ORIGINAL RPC HERE
>                                 }
>                         });
>                 } else {
>                         Window.alert("An error has occurred.  Contact your system
> administrator.");
>                 }
>         }
>
>         public final void onSuccess(T result) {
>                 uponSuccess(result);
>         }
>
>         public abstract void uponSuccess(T result);
>
> }
>
> </code>
>
> Does anybody know how I can capture the original RPC before it is sent
> so I can resubmit it?

I suppose Ray Ryan's proposal to use a command pattern for your RPC
calls [1] would help you in solving it.

[1] http://code.google.com/events/io/2009/sessions/GoogleWebToolkitBestPractices.html

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