Re: Using a variable for a field name in a filter?

Wouldn't this work?

kwargs = { var_field: "found" }
Foo.objects.filter(**kwargs)

On May 14, 3:19 pm, derek <gamesb...@gmail.com> wrote:
> Given a model Foo, with a field bar:
> Foo.objects.filter(bar = "found")
> works just fine.
>
> But, in my case, different fields are needed at different times, so I
> would like to use:
> Foo.objects.filter(var_field = "found")
> where "var_field" is a variable which will be set to the name of a
> field (such as "bar").
>
> The above is incorrect - how do I accomplish this?
>
> Thanks
> Derek
>
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