Re: Best way to present N items in table row for list

On Jul 27, 12:51 pm, Wadim <wadim.ovchare...@gmail.com> wrote:
> Hello.
> I have a list that i want to present in a table.
> Each row should have 5 items.
> For now i create the function that returns me new grouped list, that i
> use later in a template.
> def groupListByRow(list):
>         cnt=0
>         rows=[]
>         while cnt<len(list):
>                 row=[]
>                 for x in range(5):
>                         if cnt<len(list):
>                                 row.append(list[cnt])
>                         else:
>                                 row.append(None)
>                         cnt+=1
>                 rows.append(row)
>         return rows;
> is there better way to do this? May be it is possible to do it inside
> template?
> Thanks

Are you sure you need a table and you can't just make a
bunch of floating DIVs with some fixed width? If you need a
table, I would personally prefer to do this in python code,
like so:

lst = range(42)
rows = []
while lst:
row, lst = lst[:5], lst[5:]
rows.append(row + [None]*(5 - len(row)))

-ak

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