Re: [android-developers] How to detect XHDPI on Froyo?

Hi Dianne,

 

thank you for answering my question.

 

maybe i have written my problem in a wrong way^^

 

what i want to do is as i wrote to be compatible to Froyo – that means, i have some parts in my code

that checks for XHDPI devices (i know, its up to Gingerbread) but i cant remove that code ... but, these

functions arent supported in Froyo – so, what can i do to support both Froyo and xlarge devices?

I dont want to create a second app to be compatible :(

 

Btw:

can i use code such as

boolean isScreenLarge = mDisplayMetrics.densityDpi >= DisplayMetrics.DENSITY_HIGH

... maybe this can solve my problem because DENSITY_HIGH is supported.

this are constant hex values that cant be compared to greater or less as i think, or does that works ???

 

Thanks for help ;)

 

 

From: Dianne Hackborn

Sent: Sunday, May 06, 2012 10:21 PM

To: android-developers@googlegroups.com

Subject: Re: [android-developers] How to detect XHDPI on Froyo?

 

xhdpi wasn't added until GB.  It doesn't exist on Froyo, so there is no need to check for it.

 

Also saying that you are checking density to solve problems on large devices is...  wrong.  Density is screen pixel density; it has nothing to do with device/screen *size*.

On Sat, May 5, 2012 at 2:01 AM, phoenix-launcher.com <duskman72@googlemail.com> wrote:

Hi,

i want to make my app compatible to Froyo, i can downgrade most of my
code but have
no idea on how to detect XHDPI screens. Currently i have things in my
code like
"if( mDisplayDensity == DisplayMetrics.DENSITY_XHIGH)" to solve some
problems on large
devices - in the Froyo version this isnt possible because its not
supported.

Thanks for a tipp to solve that :)

Greets from Munich
Andy

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Dianne Hackborn
Android framework engineer
hackbod@android.com

Note: please don't send private questions to me, as I don't have time to provide private support, and so won't reply to such e-mails.  All such questions should be posted on public forums, where I and others can see and answer them.

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