Re: How to access HttpRequest from urls.py in Django? or better way.

Sorry!

I using request.GET['category']

在 Jun 10, 2012，9:19 PM， Daniel Roseman 写道：

On Sunday, 10 June 2012 05:21:08 UTC+1, losingle wrote:

news_info_dict should be
news_info_dict = {
    'queryset':News.published.filter(category=
request.category).all(),
    'date_field': 'pub_date',
}

I couldn't find a way to access the HttpRequest (request) object
though... Or find the better way ...

Your code doesn't set `request.category` anywhere anyway, so even if you could access request it wouldn't work.

However, this can't be done. Instead you should use the generic class-based views, subclass the appropriate one and override `get_query_set` to access `self.kwargs['category']`. See the documentation:

https://docs.djangoproject.com/en/dev/topics/class-based-views/#dynamic-filtering

--

DR. 

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