Re: Ingherited models that filter active users/records?

Or, if there is a connection between Users and People, set up a new association in the User model - say, ActivePerson - and set a condition on it:

var $hasMany = array(
'ActivePerson' => array(
'className' => 'Person',
'conditions' => array(
'ActivePerson.active' => 1
)
)
);

Then make all your finds against the User model instead of the Person model:

$people = $this->User->ActivePerson->find('all');

Might not be quite as clean, but it' works well.

On 20 Jul 2012, at 21:01, Mike Griffin wrote:

> On Fri, Jul 20, 2012 at 5:44 PM, geste <jim.hogan@gmail.com> wrote:
>> However, I find myself writing a lot of snippets in controllers that
>> essentially go "WHERE active = '1'" and that seems like it could be a pain
>> and error-prone over time.
>>
>> What I'd like to do is leave "People" alone but create a new model or model
>> called "Users" that simply flters People for active=1. And maybe a
>> corresponding model that is OldUsers and feteches active=0.
>>
>> I started to implement something like this at the controller level but then
>> asked myself why not implement at Model level. Does this seems liek a
>> rational approach. Can anyone point to some good examples outside of basic
>> API docs?
>
> The model is the perfect place to put this. Have a look at creating
> custom find types
> (http://book.cakephp.org/2.0/en/models/retrieving-your-data.html#creating-custom-find-types)
>
> You can set whatever filters you want in there.
>
> Mike.
>
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