Re: CakePHP 2.x implement edit form in ajax in a popup
Thanks for your reply Greg.
How can $load pick form which is not on the page. However I am able to display form.
I need to know how to submit this form in ajax way..
Many thanks,
Kiran
On Thu, Oct 4, 2012 at 6:06 AM, Greg Skerman <gskerman@gmail.com> wrote:
jquery, and $.load() will be your friend here.
You can just "load" the html view of the edit form into a div and show it.
not the only way to do it, but certainly the most straight forward. (then just trap the submit, serialize the form, fire off a post in jquery and close the popup, refresh the content)
On Thu, Oct 4, 2012 at 12:00 AM, Kiran <kiran0074u@gmail.com> wrote:I have read other posts and searched google before posting this here.I have a jquery popup in a view where I intend to show EDIT form and then submit using ajax.Further DetailsThere is a reservation controller. reservations on a particular date are shown in the index ctp in a table . When user clicks on edit button a div pops up. Now I need to show Edit form and submit it via Ajax.Please can somebody point me in the right direction , may be some help or some tutorial.Thanks in advance,Kiran--
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Thank you,
Kiran.
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