Re: [android-developers] onClick() is fired twice.

It doesn't work. 

In my case, the activity has a ViewPager which contains four of Fragments.

Some fragments have a button to show another activity. These buttons caused 'double-clicking' issues.

(If click a button twice very fast, then two of the same activity are shown)

I avoided this issue by overriding startActivityFromFragment in Activity. With these workaround, all of child fragments don't need to care about double-clicking issues any more. 

@Override

public void startActivityFromFragment(...) 

{

  if (subActivityStarted)

    return;

  super.startActivityFromFragment(...);

  subActivityStarted = true;

}

@Override

public void onResume() {

  subActivityStarted = false;

  super.onResume();

}

However, if you want to show an instance of DialogFragment on click, 'double-clicking issue' may happen. (shows two of the same DialogFragment)

You can avoid this issue by checking whether FragmentManager has a fragment already.

void showSomeDialog() {

  if (getFragmentManager().findFragmentByTag("dialog") != null) 

    return;

  MyDialogFragment.newInstance().show(getFragmentManager(), "dialog"); 

}

I don't like these two work around (overriding startActivityFromFragment and checking FragmentManager) but this is the best solution I found yet.

On Friday, November 9, 2012 9:58:01 AM UTC+9, TreKing wrote:

On Tue, Oct 30, 2012 at 4:57 AM, jhan <jooyu...@gmail.com> wrote:

Is there a standard way of starting activity by clicking a button without  worrying the double-clicking issues?

Disable the button after the first click and re-enable it after the activity returns?

-------------------------------------------------------------------------------------------------
TreKing - Chicago transit tracking app for Android-powered devices

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