Re: [Rails] Re: evaluating expressions left to right

meth3 -> (meth2) -> (meth1)

The logic is that meth3 has to return so that meth2 can accept,
process and return so that meth1 can accept, process and return.
Don't read nested methods like you read a book, with nested methods
the last to be nested is the first to be executed.

On Sun, Dec 23, 2012 at 2:14 AM, 7stud -- <lists@ruby-forum.com> wrote:
> In this method call:
>
> meth1(meth2(meth3))
>
> ...which value has has to be computed first so that meth1 can return?
>
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