Urls on the fly

I am looking the way to create urls on the fly.

This is a simplified version of the code I am using:

def get_urls():

    url_list = []

    for code in external_code_list:

        url_list.append(

            url(r'^%s/$' % code,

            view

            )

        )

    urlpatterns = patterns('', url_list)

    return urlpatterns

urlpatterns = get_urls()

It throws "url() takes at least 2 arguments (2 given)"

Any idea?

Thanks

--
Serge G. Spaolonzi

Cobalys Systems

http://www.cobalys.com

--
You received this message because you are subscribed to the Google Groups "Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscribe@googlegroups.com.
To post to this group, send email to django-users@googlegroups.com.
Visit this group at http://groups.google.com/group/django-users?hl=en.
For more options, visit https://groups.google.com/groups/opt_out.