Re: HttpResponse.has_header

On Sun, May 12, 2013 at 1:07 AM, Masklinn <masklinn@masklinn.net> wrote:
> On 12 mai 2013, at 05:04, Larry Martell <larry.martell@gmail.com> wrote:
>> On Sat, May 11, 2013 at 9:08 AM, Masklinn <masklinn@masklinn.net> wrote:
>>>
>>> On 2013-05-11, at 17:01 , Larry Martell wrote:
>>>
>>>> On Sat, May 11, 2013 at 8:23 AM, Masklinn <masklinn@masklinn.net> wrote:
>>>>> On 2013-05-11, at 15:57 , Larry Martell wrote:
>>>>>>
>>>>>> Yes, that is what I did. This is not in my urlconf. It's in a view
>>>>>> function. I replaced:
>>>>>>
>>>>>> return direct_to_template(request, template)
>>>>>>
>>>>>> by:
>>>>>>
>>>>>> return TemplateView.as_view(template_name=template)
>>>>>>
>>>>>> Is that not correct?
>>>>>
>>>>> Indeed not, `TemplateView.as_view(template)` is roughly equivalent to
>>>>> `functools.partial(direct_to_template, template=template)`: it's only
>>>>> one half of the operation, which returns a callable replying to
>>>>> requests.
>>>>>
>>>>> You need something along the lines of `TemplateView.as_view(template)(request)`
>>>>
>>>> I appreciate all the assistance. I tried that and got:
>>>>
>>>> TypeError: as_view() takes exactly 1 argument (2 given)
>>>
>>> Oh yeah, you need to pass it as the keyword argument "template_name"
>>> sorry about that. Basically take your code and add "(request)" at the
>>> end.
>>>
>>> If the current request is a GET obviously.
>>
>> Thanks. That got me further along. I don't understand that syntax
>> though. Never see that before.
>
> It's nothing more than a function returning a function, both being called in sequence

Very cool. Never seen that before in python.

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