Re: File wsgi.py identify SO

On Wed, Jun 19, 2013 at 3:15 PM, Hélio Miranda <helio13m@gmail.com> wrote:

I was trying this:

if os.name == 'nt':

    sys.path.append('c:/Projectos/Test/') # Windows

else:

    sys.path.append('/srv/django/OnPitch/') # other (unix)

doing so, looking at the link that you send will not give

if sys.platform('win32'):

    sys.path.append('c:/Projectos/Test/') # Windows

else:

    sys.path.append('/srv/django/OnPitch/') # other (unix)

Both sys.platform and os.name are variables, not functions.  sys.platform('win32') should be sys.platform == 'win32'

As the documentation says, os.name is another way to distinguish the OS, but os.name is more coarse.  Use whichever suits you best.

 

which is correct?

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Gustavo J. A. M. Carneiro
"The universe is always one step beyond logic." -- Frank Herbert

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