Re: Not able to send email to more than 2 email address

Dear Russell Keith-Magee

Now its working!

Thanks

On Thursday, June 13, 2013 5:00:30 AM UTC+5:30, Russell Keith-Magee wrote:

On Thu, Jun 13, 2013 at 3:28 AM, <roopas...@gmail.com> wrote:

models.py

class FollowerEmail(models.Model):      report = models.ForeignKey(Report)      email = models.CharField('Email', max_length=100)

views.py
  
def what(request):
  
    """"""
    follower = FollowerEmail.objects.filter(report=report)
    list=[]        
    for email in follower:
        list.append(email.email)
      """"""""
     if 'send_email' in request.POST:
            subject, from_email, to = 'Notification',user.email, person.parent_email
            html_content = render_to_string('incident/print.html',{'person':person,
                                                                   'report':report,
                                                                 'list':list,
                                                                  }) 
              text_content = strip_tags(html_content) 
            msg = EmailMultiAlternatives(subject, text_content, from_email, [to],bcc=[list], cc=['roopas...@gmail.com'])
              msg.attach_alternative(html_content, "text/html")
            msg.send()

The above is my view.py to send email,email is sending to "to" address properlly.Problem is with bcc tag.I am taking the email from FollowerEmail table and making a list.I am passing that list to bcc,as bcc email id list would be large,will be more than 3.
  
If list is having more than 2 email id,application is not sending  mail,if it is two or one,application is sending mail.What could be the problem

It looks to me like the problem lies with the argument you're passing to bcc. The value you're passing to bcc isn't a list of email addresses -- it's a list that contains a list of email addresses. Honestly, I'm surprised it's working even for the 1 and 2 email case. Make the argument to EmailMultiAlternatives bcc=list, and it should work.

Yours,

Russ Magee %-) 

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