Re: [android-developers] Restoring instance state for a dialog that launches another dialog

I already said where I was calling it - in an overridden showDialog method in the subclass of DialogPreference.  This is the code:

    protected void showDialog(Bundle b) {
        super.showDialog(b);
        if(onLaunch != null) {
            onLaunch.run();
        }
    }

In particular, it's being called after super.showDialog is called.  What I don't understand is why the second dialog (which is launched by the runnable) is still appearing under the first dialog.

On Saturday, November 2, 2013 6:59:42 PM UTC-4, TreKing wrote:

On Sat, Nov 2, 2013 at 5:28 PM, Michael Palmer <meicp...@gmail.com> wrote:

When onCreateDialogView is called, the Runnable is assigned a value.  This Runnable object is actually created in a method call in the custom view subclass itself.  This class stores a dialog variable.  The Runnable will show the dialog if it is both not null and not showing.  This condition happens after a call to onRestoreInstanceState with data indicating that the dialog was open - it will create a new dialog and assign it to this variable, but not show it.

I mean, how are you actually putting this Runnable to use? When and how do you call it? What method (not referring java function) are you using it execute it? Code snip if you have it.

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TreKing - Chicago transit tracking app for Android-powered devices

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