Re: Streaming images with HttpResponse?
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On Mon, Nov 18, 2013 at 1:57 PM, Alex Karargyris <akarargyris@gmail.com> wrote:
So thanks to Simon I was able to make this work. Here is the code for those who might be interested:--yield "<html>"
yield '<meta http-equiv="refresh" content="0.01" />'
yield "<body>\n"
rval, frame = settings.CAP.read()
gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)
cv2.imwrite('media/image.jpeg', gray, [int(cv2.IMWRITE_JPEG_QUALITY), 90])
x={"src": "..%s/image.jpeg" % (settings.MEDIA_URL), "alt": "Video Frame"}
yield '<img src="%(src)s" alt="%(alt)s"/>' % x
yield "</body></html>\n"
However as it doesn't stream the images but instead it saves and the html is refreshed every 0.01 secs. This does not seem to be an elegant solution because a) there is latency and b) the browser keeps reloading constantly. Some of you suggested websockets. Is there some good example for Django + Websockets for streaming images to the browser?
Thanks a lot!-Alex
On Friday, November 15, 2013 11:15:21 AM UTC-5, Alex Karargyris wrote:I have this simple app that I opens webcam and processes the frames using OpenCV. In my views.py I have the following code:def processImage():while True:rval, frame = settings.CAP.read() //Read frames from webcamgray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY) //Make frame grayscalepil_img = Image.fromarray(gray)response = HttpResponse(mimetype="image/png")pil_img.save(response, "PNG")return responseAlthough there is a while loop the function runs only once because it is broken by "return response". How could I change the code to make it run constantly?
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