Re: [Rails] Re: evaluating expressions left to right

If you think about it there is only one possible answer to that
question. How could it evaluate meth2(meth3) without evaluating meth3
first, in order to pass the result to meth2? Similarly how could it
call meth1 before it evaluated the parameter to pass to it?

Colin

On 23 December 2012 08:14, 7stud -- <lists@ruby-forum.com> wrote:
> In this method call:
>
> meth1(meth2(meth3))
>
> ...which value has has to be computed first so that meth1 can return?
>
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