Wednesday, August 14, 2013

Re: Prefilling form data doesn't seem to work

$data = $this->Model->find etc...

unset($data['Model']['id'];

$this->data = $data;


On 14 Aug 2013, at 19:40, Anja Liebermann <cake@anjaliebermann.de> wrote:

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> Hi David,
>
>
> this is how I would do it:
>
> copy your edit method and rename it to "copy". Like with edit you fetch
> the data which should be cloned and show then in a view "copy.ctp" which
> has a form like for adding a new record.
> Then when the user submits you call your copy method again in the "hey I
> have post data" fork and save it as a new record by unsetting a probably
> exiting id.
>
> That should do it.
>
> HTH!
> Anja
>
>
>
> Am 14.08.2013 20:22, schrieb David Carr:
>> Here's what I am trying to accomplish:
>>
>> A user fills out a form, saves a record. At some later date they wish to
>> "clone" this record, but may want to make a few tweaks. This "clone"
>> functionality should direct them to a form that is pre-filled with the
>> previous record's data so that they can review it, edit as needed, and
>> submit it as a new record.
>>
>> What I'm trying:
>>
>> I've modified my add() function to accept a parameters:
>>
>> function add($cloneid = NULL)
>>
>> Then created a Clone link that sends them to <site>/model/add/<id>
>>
>> Then, I get the data from that model:
>>
>> $clone_source = $this->Model->findById($cloneid);
>> $this->data['Model']['field1'] = $clone_source['Model']['field1'];
>>
>> and so on. Based on Google searching and other posts, this should work.
>> But what actually happens is that upon clicking the 'Clone' link, the user
>> is directed and the form submits itself immediately (failing to save the
>> record, since it fails validation) and the user never actually sees the
>> form.
>>
>> What am I doing wrong? (Also I should note, there are relational models
>> present, but I don't think this should be the cause of any problems...I
>> hope).
>>
>
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